Re (2): , ,
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SDA 12:07:41 10/11/19100
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Re: , , ,
12:16:05 09/11/19100
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. . . : - : 0,1,4,9,16,9,4,1,0 - : 11,7,3,14,1,16,5,10,13 - : = -(4 * (2/9)*log (2/9) +
2 + (1/9)*log (1/9)) =
2 = -( 4*0.222*(-2.169) + 0.111*(-3.16) ) = 2.27 - Eb = 9*(1/9)*log (1/9) = 3.16
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0 . - . = 4/9 = 0.4(4) . . dZ/dt = k1 * 2.7 . - . 0.4(4)/(k1*2.7) = 0.16/k1 .. = (9*8)/(2*8+9*3) = 1.67 - : 11,7,3,14,0,16,5,10,13
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1 . - . = 9/9 = 1 . . dZ/dt = k1 * 7.4 . - . 1/(k1*7.4) = 0.13/k1 .. = (9*8)/(2*8+9*2) = 2.11
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